AMC 8 2000 Problem 7

AMC8 2000 年第 7 题

表达式与运算★★☆☆☆

What is the minimum possible product of three different numbers of the set

\{-8,-6,-4,0,3,5,7\}

集合｛-8，-6，-4，0，3，5，7｝中的三个不同的元素的乘积的最小可能值是多少？

A.-336
B.-280
C.-210
D.-192
E.0

正确答案 · Correct Answer

解析 · Solution

Solution 1

The only way to get a negative product using three numbers is to multiply one negative number and two positives or three negatives. Only two reasonable choices exist:

(-8)\times(-6)\times(-4) = (-8)\times(24) = -192

and

(-8)\times5×7 = (-8)\times35 = -280

. The latter is smaller, so

\text{(B)\ -280}

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