AMC 8 2000 Problem 8

AMC8 2000 年第 8 题

基本计数原理★★☆☆☆

Three dice with faces numbered 1 through 6 are stacked as shown. Seven of the eighteen faces are visible, leaving eleven faces hidden (back, bottom, between). The total number of dots NOT visible in this view is

3 个各个面上分别标有 1 到 6 的数字的骰子如图所示堆叠起来。18 个面只有 7 个面可见。其余 11 个面不可见（后面，底面以及两个骰子之间的面）。图示所示的角度所看不到的面上的点数总和是多少？

A.21
B.22
C.31
D.41
E.53

正确答案 · Correct Answer

解析 · Solution

Solution 1

The numbers on one die total 1+2+3+4+5+6 = 21, so the numbers on the three dice total 63. Numbers 1, 1, 2, 3, 4, 5, 6 are visible, and these total 22. This leaves

63 - 22 = \text{(D) 41}

not seen.

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