AMC 8 2002 Problem 3

AMC8 2002 年第 3 题

表达式与运算★☆☆☆☆

What is the smallest possible average of four distinct positive even integers?

4 个不同的正偶数的平均值最小可能是多少？

正确答案 · Correct Answer

解析 · Solution

Solution 1

In order to get the smallest possible average, we want the 4 even numbers to be as small as possible. The first 4 positive even numbers are 2, 4, 6, and 8. Their average is

\displaystyle \frac{2+4+6+8}{4} = \frac{20}{4} = \text{(C) } 5

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