AMC 8 2002 Problem 4
AMC8 2002 年第 4 题
表达式与运算★★☆☆☆
The year 2002 is a palindrome (a number that reads the same from left to right as it does from right to left). What is the product of the digits of the next year after 2002 that is a palindrome?
2002 年这个年份的数字是个回环数（是一个从左向右读和从右向左读一样的数）。那么 2002 年之后的下一个也是回环数的年份的各个位上数字之积是多少？
- A.0
- B.4
- C.9
- D.16
- E.25
正确答案 · Correct Answer
B
解析 · Solution
Solution 1
The palindrome right after 2002 is 2112. The product of the digits of 2112 is .
The palindrome formula is to add 110 to the number in order to get the next palindrome, a palindrome needs to be in the form as ABBA. We can use this in this case to get 2112. 2*1*1*2=4. Therefore, the answer is .
继续练习