AMC 8 2004 Problem 19

AMC8 2004 年第 19

余数与同余★★★☆☆
Problem A whole number larger than 2 leaves a remainder of 2 when divided by each of the numbers $3, 4, 5,$ and $6$. The smallest such number lies between which two numbers?
一个大于 2 的正整数分别除以 3,4,5 和 6,所得余数均为 2。那么这个正整数的最小可能值在哪两个数之间?
  1. A.40 and4940\ \text{and}49
  2. B.60 and 7960 \text{ and } 79
  3. C.100 and129100\ \text{and}129
  4. D.210 and249210\ \text{and}249
  5. E.320 and369320\ \text{and}369

正确答案 · Correct Answer

B

解析 · Solution

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